27 lines
1.4 KiB
Python
27 lines
1.4 KiB
Python
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# Check that a string that needs a comment has one
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# # Copyright (C) 2015 Red Hat, Inc.
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#
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# This copyrighted material is made available to anyone wishing to use,
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# modify, copy, or redistribute it subject to the terms and conditions of
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# the GNU Lesser General Public License v.2, or (at your option) any later
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# version. This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY expressed or implied, including the implied
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# warranties of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See
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# the GNU Lesser General Public License for more details. You should have
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# received a copy of the GNU Lesser General Public License along with this
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# program; if not, write to the Free Software Foundation, Inc., 51 Franklin
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# Street, Fifth Floor, Boston, MA 02110-1301, USA. Any Red Hat trademarks
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# that are incorporated in the source code or documentation are not subject
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# to the GNU Lesser General Public License and may only be used or
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# replicated with the express permission of Red Hat, Inc.
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#
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# Red Hat Author(s): David Shea <dshea@redhat.com>
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def test_comment(poentry):
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# Single-character translatable strings (e.g., the 'c' of press c to
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# continue) need some additional context in order to make sense. Make
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# sure that they have it.
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if len(poentry.msgid) == 1 and not poentry.comment:
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raise AssertionError("Single-character string missing a comment.")
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